(+25x^2+125x+125x+625)-1500=0

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Solution for (+25x^2+125x+125x+625)-1500=0 equation:



(+25x^2+125x+125x+625)-1500=0
We get rid of parentheses
25x^2+125x+125x+625-1500=0
We add all the numbers together, and all the variables
25x^2+250x-875=0
a = 25; b = 250; c = -875;
Δ = b2-4ac
Δ = 2502-4·25·(-875)
Δ = 150000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{150000}=\sqrt{10000*15}=\sqrt{10000}*\sqrt{15}=100\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(250)-100\sqrt{15}}{2*25}=\frac{-250-100\sqrt{15}}{50} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(250)+100\sqrt{15}}{2*25}=\frac{-250+100\sqrt{15}}{50} $

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